0.8(3x+20)=1.2(1-x)

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Solution for 0.8(3x+20)=1.2(1-x) equation:



0.8(3x+20)=1.2(1-x)
We move all terms to the left:
0.8(3x+20)-(1.2(1-x))=0
We add all the numbers together, and all the variables
0.8(3x+20)-(1.2(-1x+1))=0
We multiply parentheses
2.4x-(1.2(-1x+1))+16=0
We calculate terms in parentheses: -(1.2(-1x+1)), so:
1.2(-1x+1)
We multiply parentheses
-1.2x+1.2
Back to the equation:
-(-1.2x+1.2)
We get rid of parentheses
2.4x+1.2x-1.2+16=0
We add all the numbers together, and all the variables
3.6x+14.8=0
We move all terms containing x to the left, all other terms to the right
3.6x=-14.8
x=-14.8/3.6
x=-4+0.4/3.6

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