0.7z+1.9+0.1z=1/4(20+2y)

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Solution for 0.7z+1.9+0.1z=1/4(20+2y) equation: 


x in (-oo:+oo)

0.7*z+0.1*z+1.9 = (1/4)*(2*y+20) // - (1/4)*(2*y+20)

0.7*z-((1/4)*(2*y+20))+0.1*z+1.9 = 0

(-1/4)*(2*y+20)+0.7*z+0.1*z+1.9 = 0

0.7*z-1/4*(2*y+20)+0.1*z+1.9 = 0

0.7*z-1/4*(2*y+20)+0.1*z+1.9 = 0

0.7*z-1/2*y+0.1*z-5+1.9 = 0

0.8*z-1/2*y-5+1.9 = 0

0.8*z-1/2*y-3.1 = 0

0.8*z-1/2*y-3.1 = 0

x belongs to the empty set

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