0.75(4-12z)+2=12-(4z+5)

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Solution for 0.75(4-12z)+2=12-(4z+5) equation:



0.75(4-12z)+2=12-(4z+5)
We move all terms to the left:
0.75(4-12z)+2-(12-(4z+5))=0
We add all the numbers together, and all the variables
0.75(-12z+4)-(12-(4z+5))+2=0
We multiply parentheses
-9z-(12-(4z+5))+3+2=0
We calculate terms in parentheses: -(12-(4z+5)), so:
12-(4z+5)
determiningTheFunctionDomain -(4z+5)+12
We get rid of parentheses
-4z-5+12
We add all the numbers together, and all the variables
-4z+7
Back to the equation:
-(-4z+7)
We add all the numbers together, and all the variables
-9z-(-4z+7)+5=0
We get rid of parentheses
-9z+4z-7+5=0
We add all the numbers together, and all the variables
-5z-2=0
We move all terms containing z to the left, all other terms to the right
-5z=2
z=2/-5
z=-2/5

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