0.6(y+2)-0.2(2-y)=1

Solution for 0.6(y+2)-0.2(2-y)=1 equation:

Simplifying
0.6(y + 2) + -0.2(2 + -1y) = 1

Reorder the terms:
0.6(2 + y) + -0.2(2 + -1y) = 1
(2 * 0.6 + y * 0.6) + -0.2(2 + -1y) = 1
(1.2 + 0.6y) + -0.2(2 + -1y) = 1
1.2 + 0.6y + (2 * -0.2 + -1y * -0.2) = 1
1.2 + 0.6y + (-0.4 + 0.2y) = 1

Reorder the terms:
1.2 + -0.4 + 0.6y + 0.2y = 1

Combine like terms: 1.2 + -0.4 = 0.8
0.8 + 0.6y + 0.2y = 1

Combine like terms: 0.6y + 0.2y = 0.8y
0.8 + 0.8y = 1

Solving
0.8 + 0.8y = 1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-0.8' to each side of the equation.
0.8 + -0.8 + 0.8y = 1 + -0.8

Combine like terms: 0.8 + -0.8 = 0.0
0.0 + 0.8y = 1 + -0.8
0.8y = 1 + -0.8

Combine like terms: 1 + -0.8 = 0.2
0.8y = 0.2

Divide each side by '0.8'.
y = 0.25

Simplifying
y = 0.25