0.6(t+28)=-3(4-t)

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Solution for 0.6(t+28)=-3(4-t) equation: 



0.6(t+28)=-3(4-t)

We move all terms to the left:

0.6(t+28)-(-3(4-t))=0

We add all the numbers together, and all the variables

0.6(t+28)-(-3(-1t+4))=0

We multiply parentheses

0.6t-(-3(-1t+4))+16.8=0



We calculate terms in parentheses: -(-3(-1t+4)), so:

-3(-1t+4)

We multiply parentheses

3t-12

Back to the equation:

-(3t-12)



We get rid of parentheses

0.6t-3t+12+16.8=0

We add all the numbers together, and all the variables

-2.4t+28.8=0

We move all terms containing t to the left, all other terms to the right

-2.4t=-28.8

t=-28.8/-2.4

t=12+3.5527136788005E-15/2.4

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