0.6(4-2x)=20.5-(3x+10)

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Solution for 0.6(4-2x)=20.5-(3x+10) equation: 



0.6(4-2x)=20.5-(3x+10)

We move all terms to the left:

0.6(4-2x)-(20.5-(3x+10))=0

We add all the numbers together, and all the variables

0.6(-2x+4)-(20.5-(3x+10))=0

We multiply parentheses

-1.2x-(20.5-(3x+10))+2.4=0



We calculate terms in parentheses: -(20.5-(3x+10)), so:

20.5-(3x+10)

determiningTheFunctionDomain
-(3x+10)+20.5

We get rid of parentheses

-3x-10+20.5

We add all the numbers together, and all the variables

-3x+10.5

Back to the equation:

-(-3x+10.5)



We get rid of parentheses

-1.2x+3x-10.5+2.4=0

We add all the numbers together, and all the variables

1.8x-8.1=0

We move all terms containing x to the left, all other terms to the right

1.8x=8.1

x=8.1/1.8

x=4+0.9/1.8

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