0.6(4-2x)=20.4-(3x+10)

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Solution for 0.6(4-2x)=20.4-(3x+10) equation:



0.6(4-2x)=20.4-(3x+10)
We move all terms to the left:
0.6(4-2x)-(20.4-(3x+10))=0
We add all the numbers together, and all the variables
0.6(-2x+4)-(20.4-(3x+10))=0
We multiply parentheses
-1.2x-(20.4-(3x+10))+2.4=0
We calculate terms in parentheses: -(20.4-(3x+10)), so:
20.4-(3x+10)
determiningTheFunctionDomain -(3x+10)+20.4
We get rid of parentheses
-3x-10+20.4
We add all the numbers together, and all the variables
-3x+10.4
Back to the equation:
-(-3x+10.4)
We get rid of parentheses
-1.2x+3x-10.4+2.4=0
We add all the numbers together, and all the variables
1.8x-8=0
We move all terms containing x to the left, all other terms to the right
1.8x=8
x=8/1.8
x=4+0.8/1.8

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