0.6(1-c)=0.1(2-c)

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Solution for 0.6(1-c)=0.1(2-c) equation: 



0.6(1-c)=0.1(2-c)

We move all terms to the left:

0.6(1-c)-(0.1(2-c))=0

We add all the numbers together, and all the variables

0.6(-1c+1)-(0.1(-1c+2))=0

We multiply parentheses

-0.6c-(0.1(-1c+2))+0.6=0



We calculate terms in parentheses: -(0.1(-1c+2)), so:

0.1(-1c+2)

We multiply parentheses

-0.1c+0.2

Back to the equation:

-(-0.1c+0.2)



We get rid of parentheses

-0.6c+0.1c-0.2+0.6=0

We add all the numbers together, and all the variables

-0.5c+0.4=0

We move all terms containing c to the left, all other terms to the right

-0.5c=-0.4

c=-0.4/-0.5

c=0.4/0.5

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