0.5x+(3.1x-2)=(x-5)-(0.2x+1.8)

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Solution for 0.5x+(3.1x-2)=(x-5)-(0.2x+1.8) equation: 



0.5x+(3.1x-2)=(x-5)-(0.2x+1.8)

We move all terms to the left:

0.5x+(3.1x-2)-((x-5)-(0.2x+1.8))=0

We get rid of parentheses

0.5x+3.1x-((x-5)-(0.2x+1.8))-2=0



We calculate terms in parentheses: -((x-5)-(0.2x+1.8)), so:

(x-5)-(0.2x+1.8)

We get rid of parentheses

x-0.2x-5-1.8

We add all the numbers together, and all the variables

0.8x-6.8

Back to the equation:

-(0.8x-6.8)



We add all the numbers together, and all the variables

3.6x-(0.8x-6.8)-2=0

We get rid of parentheses

3.6x-0.8x+6.8-2=0

We add all the numbers together, and all the variables

2.8x+4.8=0

We move all terms containing x to the left, all other terms to the right

2.8x=-4.8

x=-4.8/2.8

x=-1+1/1.4

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