0.5m(m+4)=3(m-1)

Solution for 0.5m(m+4)=3(m-1) equation:

0.5m(m+4)=3(m-1)

We move all terms to the left:

0.5m(m+4)-(3(m-1))=0

We multiply parentheses

0m^2+0m-(3(m-1))=0


We calculate terms in parentheses: -(3(m-1)), so:

3(m-1)

We multiply parentheses

3m-3

Back to the equation:

-(3m-3)


We add all the numbers together, and all the variables

m^2+m-(3m-3)=0

We get rid of parentheses

m^2+m-3m+3=0

We add all the numbers together, and all the variables

m^2-2m+3=0

a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation