0.5h+6-(2/3)h=0

Solution for 0.5h+6-(2/3)h=0 equation:

0.5h+6-(2/3)h=0


Domain of the equation: 3)h!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

0.5h-(+2/3)h+6=0

We multiply parentheses

-2h^2+0.5h+6=0

a = -2; b = 0.5; c = +6;
Δ = b2-4ac
Δ = 0.52-4·(-2)·6
Δ = 48.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{48.25}}{2*-2}=\frac{-0.5-\sqrt{48.25}}{-4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{48.25}}{2*-2}=\frac{-0.5+\sqrt{48.25}}{-4}
$