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0.5(r2.75)=3
We move all terms to the left:
0.5(r2.75)-(3)=0
We add all the numbers together, and all the variables
0.5(+r2.75)-3=0
We multiply parentheses
0.5r^2-3=0
a = 0.5; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·0.5·(-3)
Δ = 6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6}}{2*0.5}=\frac{0-\sqrt{6}}{1} =-\frac{\sqrt{}}{1} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6}}{2*0.5}=\frac{0+\sqrt{6}}{1} =\frac{\sqrt{}}{1} $
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