0.5(4x-2)-2(3x+3)=9+2(x+4)

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Solution for 0.5(4x-2)-2(3x+3)=9+2(x+4) equation: 



0.5(4x-2)-2(3x+3)=9+2(x+4)

We move all terms to the left:

0.5(4x-2)-2(3x+3)-(9+2(x+4))=0

We multiply parentheses

2x-6x-(9+2(x+4))-1-6=0



We calculate terms in parentheses: -(9+2(x+4)), so:

9+2(x+4)

determiningTheFunctionDomain
2(x+4)+9

We multiply parentheses

2x+8+9

We add all the numbers together, and all the variables

2x+17

Back to the equation:

-(2x+17)



We add all the numbers together, and all the variables

-4x-(2x+17)-7=0

We get rid of parentheses

-4x-2x-17-7=0

We add all the numbers together, and all the variables

-6x-24=0

We move all terms containing x to the left, all other terms to the right

-6x=24

x=24/-6

x=-4

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