0.5(2x)+(-0.2)(10)=1x+-2

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Solution for 0.5(2x)+(-0.2)(10)=1x+-2 equation: 



0.5(2x)+(-0.2)(10)=1x+-2

We move all terms to the left:

0.5(2x)+(-0.2)(10)-(1x+-2)=0

We add all the numbers together, and all the variables

0.52x-(x-2)+(-0.2)10=0

We add all the numbers together, and all the variables

0.52x-(x-2)-2=0

We get rid of parentheses

0.52x-x+2-2=0

We add all the numbers together, and all the variables

-0.48x=0

x=0/-0.48

x=0

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