0.5(28+2x)=5(1x-2)

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Solution for 0.5(28+2x)=5(1x-2) equation: 



0.5(28+2x)=5(1x-2)

We move all terms to the left:

0.5(28+2x)-(5(1x-2))=0

We add all the numbers together, and all the variables

0.5(2x+28)-(5(x-2))=0

We multiply parentheses

x-(5(x-2))+14=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

x-5x+10+14=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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