0.5(10+x)=x(3-2)+1

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Solution for 0.5(10+x)=x(3-2)+1 equation:



0.5(10+x)=x(3-2)+1
We move all terms to the left:
0.5(10+x)-(x(3-2)+1)=0
We add all the numbers together, and all the variables
0.5(x+10)-(x1+1)=0
We multiply parentheses
0.5x-(x1+1)+5=0
We get rid of parentheses
0.5x-x1-1+5=0
We add all the numbers together, and all the variables
-0.5x+4=0
We move all terms containing x to the left, all other terms to the right
-0.5x=-4
x=-4/-0.5
x=+8

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