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0.44=4.1x^2
We move all terms to the left:
0.44-(4.1x^2)=0
We get rid of parentheses
-4.1x^2+0.44=0
a = -4.1; b = 0; c = +0.44;
Δ = b2-4ac
Δ = 02-4·(-4.1)·0.44
Δ = 7.216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{7.216}}{2*-4.1}=\frac{0-\sqrt{7.216}}{-8.2} =-\frac{\sqrt{}}{-8.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{7.216}}{2*-4.1}=\frac{0+\sqrt{7.216}}{-8.2} =\frac{\sqrt{}}{-8.2} $
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