0.40x+0.05(12-x)=0.10(-29)

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Solution for 0.40x+0.05(12-x)=0.10(-29) equation: 



0.40x+0.05(12-x)=0.10(-29)

We move all terms to the left:

0.40x+0.05(12-x)-(0.10(-29))=0

We add all the numbers together, and all the variables

0.40x+0.05(-1x+12)-(0.10(-29))=0

We add all the numbers together, and all the variables

0.40x+0.05(-1x+12)+2.9=0

We multiply parentheses

0.40x-0.05x+0.6+2.9=0

We add all the numbers together, and all the variables

0.35x+3.5=0

We move all terms containing x to the left, all other terms to the right

0.35x=-3.5

x=-3.5/0.35

x=-10

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