0.4(5+2x)-0.5=3(0.3x+0.7)-0.9x

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Solution for 0.4(5+2x)-0.5=3(0.3x+0.7)-0.9x equation: 



0.4(5+2x)-0.5=3(0.3x+0.7)-0.9x

We move all terms to the left:

0.4(5+2x)-0.5-(3(0.3x+0.7)-0.9x)=0

We add all the numbers together, and all the variables

0.4(2x+5)-(3(0.3x+0.7)-0.9x)-0.5=0

We multiply parentheses

0.8x-(3(0.3x+0.7)-0.9x)+2-0.5=0



We calculate terms in parentheses: -(3(0.3x+0.7)-0.9x), so:

3(0.3x+0.7)-0.9x

We add all the numbers together, and all the variables

-0.9x+3(0.3x+0.7)

We multiply parentheses

-0.9x+0x+2.1

We add all the numbers together, and all the variables

0.1x+2.1

Back to the equation:

-(0.1x+2.1)



We add all the numbers together, and all the variables

0.8x-(0.1x+2.1)+1.5=0

We get rid of parentheses

0.8x-0.1x-2.1+1.5=0

We add all the numbers together, and all the variables

0.7x-0.6=0

We move all terms containing x to the left, all other terms to the right

0.7x=0.6

x=0.6/0.7

x=0.6/0.7

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