0.4(3x+1)=40+3x

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Solution for 0.4(3x+1)=40+3x equation: 



0.4(3x+1)=40+3x

We move all terms to the left:

0.4(3x+1)-(40+3x)=0

We add all the numbers together, and all the variables

0.4(3x+1)-(3x+40)=0

We multiply parentheses

1.2x-(3x+40)+0.4=0

We get rid of parentheses

1.2x-3x-40+0.4=0

We add all the numbers together, and all the variables

-1.8x-39.6=0

We move all terms containing x to the left, all other terms to the right

-1.8x=39.6

x=39.6/-1.8

x=-22

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