0.4(2x+8)0.4=0.2(4x-12)+16x

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Solution for 0.4(2x+8)0.4=0.2(4x-12)+16x equation: 



0.4(2x+8)0.4=0.2(4x-12)+16x

We move all terms to the left:

0.4(2x+8)0.4-(0.2(4x-12)+16x)=0

We multiply parentheses

0.32x-(0.2(4x-12)+16x)+1.28=0



We calculate terms in parentheses: -(0.2(4x-12)+16x), so:

0.2(4x-12)+16x

We add all the numbers together, and all the variables

16x+0.2(4x-12)

We multiply parentheses

16x+0.8x-2.4

We add all the numbers together, and all the variables

16.8x-2.4

Back to the equation:

-(16.8x-2.4)



We get rid of parentheses

0.32x-16.8x+2.4+1.28=0

We add all the numbers together, and all the variables

-16.48x+3.68=0

We move all terms containing x to the left, all other terms to the right

-16.48x=-3.68

x=-3.68/-16.48

x=2.1904761904762/9.8095238095238

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