0.3x2+0.1x=-0.02

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Solution for 0.3x2+0.1x=-0.02 equation: 



0.3x^2+0.1x=-0.02

We move all terms to the left:

0.3x^2+0.1x-(-0.02)=0

We add all the numbers together, and all the variables

0.3x^2+0.1x+0.02=0

a = 0.3; b = 0.1; c = +0.02;
Δ = b2-4ac
Δ = 0.12-4·0.3·0.02
Δ = -0.014
Delta is less than zero, so there is no solution for the equation

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