0.3x(12x-16)=0.4(12x-3x)

Solution for 0.3x(12x-16)=0.4(12x-3x) equation:

0.3x(12x-16)=0.4(12x-3x)

We move all terms to the left:

0.3x(12x-16)-(0.4(12x-3x))=0

We add all the numbers together, and all the variables

0.3x(12x-16)-(0.4(+9x))=0

We multiply parentheses

0x^2+0x-(0.4(+9x))=0


We calculate terms in parentheses: -(0.4(+9x)), so:

0.4(+9x)

We multiply parentheses

3.6x

Back to the equation:

-(3.6x)


We add all the numbers together, and all the variables

0x^2+0x-(+3.6x)=0

We add all the numbers together, and all the variables

x^2+x-(+3.6x)=0

We get rid of parentheses

x^2+x-3.6x=0

We add all the numbers together, and all the variables

x^2-2.6x=0

a = 1; b = -2.6; c = 0;
Δ = b2-4ac
Δ = -2.62-4·1·0
Δ = 6.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.6)-\sqrt{6.76}}{2*1}=\frac{2.6-\sqrt{6.76}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.6)+\sqrt{6.76}}{2*1}=\frac{2.6+\sqrt{6.76}}{2}
$