0.3(x-2)+0.5=1-0.2(4-2x)-0.5

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Solution for 0.3(x-2)+0.5=1-0.2(4-2x)-0.5 equation: 



0.3(x-2)+0.5=1-0.2(4-2x)-0.5

We move all terms to the left:

0.3(x-2)+0.5-(1-0.2(4-2x)-0.5)=0

We add all the numbers together, and all the variables

0.3(x-2)-(1-0.2(-2x+4)-0.5)+0.5=0

We multiply parentheses

0.3x-(1-0.2(-2x+4)-0.5)-0.6+0.5=0



We calculate terms in parentheses: -(1-0.2(-2x+4)-0.5), so:

1-0.2(-2x+4)-0.5

determiningTheFunctionDomain
-0.2(-2x+4)+1-0.5

We add all the numbers together, and all the variables

-0.2(-2x+4)+0.5

We multiply parentheses

0.4x-0.8+0.5

We add all the numbers together, and all the variables

0.4x-0.3

Back to the equation:

-(0.4x-0.3)



We add all the numbers together, and all the variables

0.3x-(0.4x-0.3)-0.1=0

We get rid of parentheses

0.3x-0.4x+0.3-0.1=0

We add all the numbers together, and all the variables

-0.1x+0.2=0

We move all terms containing x to the left, all other terms to the right

-0.1x=-0.2

x=-0.2/-0.1

x=+2

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