0.3(2x-1.62)-2.22=7+2.77(3x+1)

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Solution for 0.3(2x-1.62)-2.22=7+2.77(3x+1) equation: 



0.3(2x-1.62)-2.22=7+2.77(3x+1)

We move all terms to the left:

0.3(2x-1.62)-2.22-(7+2.77(3x+1))=0

We multiply parentheses

0.6x-(7+2.77(3x+1))-0.486-2.22=0



We calculate terms in parentheses: -(7+2.77(3x+1)), so:

7+2.77(3x+1)

determiningTheFunctionDomain
2.77(3x+1)+7

We multiply parentheses

8.31x+2.77+7

We add all the numbers together, and all the variables

8.31x+9.77

Back to the equation:

-(8.31x+9.77)



We add all the numbers together, and all the variables

0.6x-(8.31x+9.77)-2.706=0

We get rid of parentheses

0.6x-8.31x-9.77-2.706=0

We add all the numbers together, and all the variables

-7.71x-12.476=0

We move all terms containing x to the left, all other terms to the right

-7.71x=12.476

x=12.476/-7.71

x=-1+2.6987542468856/4.365798414496

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