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0.2x(x+2)-0.4(x+2)=0.2x-0.4
We move all terms to the left:
0.2x(x+2)-0.4(x+2)-(0.2x-0.4)=0
We multiply parentheses
0x^2+0x-0.4x-(0.2x-0.4)-0.8=0
We get rid of parentheses
0x^2+0x-0.4x-0.2x+0.4-0.8=0
We add all the numbers together, and all the variables
x^2+0.4x-0.4=0
a = 1; b = 0.4; c = -0.4;
Δ = b2-4ac
Δ = 0.42-4·1·(-0.4)
Δ = 1.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{1.76}}{2*1}=\frac{-0.4-\sqrt{1.76}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{1.76}}{2*1}=\frac{-0.4+\sqrt{1.76}}{2} $
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