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0.2x(7+2x)=0.4x+11.4
We move all terms to the left:
0.2x(7+2x)-(0.4x+11.4)=0
We add all the numbers together, and all the variables
0.2x(2x+7)-(0.4x+11.4)=0
We multiply parentheses
0x^2+0x-(0.4x+11.4)=0
We get rid of parentheses
0x^2+0x-0.4x-11.4=0
We add all the numbers together, and all the variables
x^2+0.6x-11.4=0
a = 1; b = 0.6; c = -11.4;
Δ = b2-4ac
Δ = 0.62-4·1·(-11.4)
Δ = 45.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{45.96}}{2*1}=\frac{-0.6-\sqrt{45.96}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{45.96}}{2*1}=\frac{-0.6+\sqrt{45.96}}{2} $
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