0.26-0.02(x+2)=0.03(1-x)

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Solution for 0.26-0.02(x+2)=0.03(1-x) equation: 



0.26-0.02(x+2)=0.03(1-x)

We move all terms to the left:

0.26-0.02(x+2)-(0.03(1-x))=0

We add all the numbers together, and all the variables

-0.02(x+2)-(0.03(-1x+1))+0.26=0

We multiply parentheses

-0.02x-(0.03(-1x+1))-0.04+0.26=0



We calculate terms in parentheses: -(0.03(-1x+1)), so:

0.03(-1x+1)

We multiply parentheses

-0.03x+0.03

Back to the equation:

-(-0.03x+0.03)



We add all the numbers together, and all the variables

-0.02x-(-0.03x+0.03)+0.22=0

We get rid of parentheses

-0.02x+0.03x-0.03+0.22=0

We add all the numbers together, and all the variables

0.01x+0.19=0

We move all terms containing x to the left, all other terms to the right

0.01x=-0.19

x=-0.19/0.01

x=-19

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