0.25x+0.05(12-x)=0.10(22)

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Solution for 0.25x+0.05(12-x)=0.10(22) equation:



0.25x+0.05(12-x)=0.10(22)
We move all terms to the left:
0.25x+0.05(12-x)-(0.10(22))=0
We add all the numbers together, and all the variables
0.25x+0.05(-1x+12)-(0.1022)=0
We add all the numbers together, and all the variables
0.25x+0.05(-1x+12)-0.1022=0
We multiply parentheses
0.25x-0.05x+0.6-0.1022=0
We add all the numbers together, and all the variables
0.2x+0.4978=0
We move all terms containing x to the left, all other terms to the right
0.2x=-0.4978
x=-0.4978/0.2
x=-2+0.0978/0.2

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