0.25cos(2t)+cos(t)+2=0

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Solution for 0.25cos(2t)+cos(t)+2=0 equation:


Simplifying
0.25cos(2t) + cos(t) + 2 = 0

Remove parenthesis around (2t)
0.25cos * 2t + cos(t) + 2 = 0

Reorder the terms for easier multiplication:
0.25 * 2cos * t + cos(t) + 2 = 0

Multiply 0.25 * 2
0.5cos * t + cos(t) + 2 = 0

Multiply cos * t
0.5cost + cos(t) + 2 = 0

Multiply cos * t
0.5cost + cost + 2 = 0

Reorder the terms:
2 + 0.5cost + cost = 0

Combine like terms: 0.5cost + cost = 1.5cost
2 + 1.5cost = 0

Solving
2 + 1.5cost = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 1.5cost = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 1.5cost = 0 + -2
1.5cost = 0 + -2

Combine like terms: 0 + -2 = -2
1.5cost = -2

Divide each side by '1.5ost'.
c = -1.333333333o-1s-1t-1

Simplifying
c = -1.333333333o-1s-1t-1

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