0.25(x+12)-0.3(2x-20)=0.2(x-20)-0.5(x-8)

Solution for 0.25(x+12)-0.3(2x-20)=0.2(x-20)-0.5(x-8) equation:

0.25(x+12)-0.3(2x-20)=0.2(x-20)-0.5(x-8)

We move all terms to the left:

0.25(x+12)-0.3(2x-20)-(0.2(x-20)-0.5(x-8))=0

We multiply parentheses

0.25x-0.6x-(0.2(x-20)-0.5(x-8))+3+6=0


We calculate terms in parentheses: -(0.2(x-20)-0.5(x-8)), so:

0.2(x-20)-0.5(x-8)

We multiply parentheses

0.2x-0.5x-4+4

We add all the numbers together, and all the variables

-0.3x

Back to the equation:

-(-0.3x)


We add all the numbers together, and all the variables

-0.35x-(-0.3x)+9=0

We get rid of parentheses

-0.35x+0.3x+9=0

We add all the numbers together, and all the variables

-0.05x+9=0

We move all terms containing x to the left, all other terms to the right

-0.05x=-9

x=-9/-0.05

x=+180