0.25(t+12)-0.3(2t-20)=0.2(t+20)-0.5(t-8)

Solution for 0.25(t+12)-0.3(2t-20)=0.2(t+20)-0.5(t-8) equation:

0.25(t+12)-0.3(2t-20)=0.2(t+20)-0.5(t-8)

We move all terms to the left:

0.25(t+12)-0.3(2t-20)-(0.2(t+20)-0.5(t-8))=0

We multiply parentheses

0.25t-0.6t-(0.2(t+20)-0.5(t-8))+3+6=0


We calculate terms in parentheses: -(0.2(t+20)-0.5(t-8)), so:

0.2(t+20)-0.5(t-8)

We multiply parentheses

0.2t-0.5t+4+4

We add all the numbers together, and all the variables

-0.3t+8

Back to the equation:

-(-0.3t+8)


We add all the numbers together, and all the variables

-0.35t-(-0.3t+8)+9=0

We get rid of parentheses

-0.35t+0.3t-8+9=0

We add all the numbers together, and all the variables

-0.05t+1=0

We move all terms containing t to the left, all other terms to the right

-0.05t=-1

t=-1/-0.05

t=+20