0.25(4b+12b)=1.5(4b-28)

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Solution for 0.25(4b+12b)=1.5(4b-28) equation: 



0.25(4b+12b)=1.5(4b-28)

We move all terms to the left:

0.25(4b+12b)-(1.5(4b-28))=0

We add all the numbers together, and all the variables

0.25(+16b)-(1.5(4b-28))=0

We multiply parentheses

4b-(1.5(4b-28))=0



We calculate terms in parentheses: -(1.5(4b-28)), so:

1.5(4b-28)

We multiply parentheses

6b-42

Back to the equation:

-(6b-42)



We get rid of parentheses

4b-6b+42=0

We add all the numbers together, and all the variables

-2b+42=0

We move all terms containing b to the left, all other terms to the right

-2b=-42

b=-42/-2

b=+21

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