0.25(20+4y)-0.5(10+2y)=

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Solution for 0.25(20+4y)-0.5(10+2y)= equation: 


Simplifying
0.25(20 + 4y) + -0.5(10 + 2y) = 0
(20 * 0.25 + 4y * 0.25) + -0.5(10 + 2y) = 0
(5 + 1y) + -0.5(10 + 2y) = 0
5 + 1y + (10 * -0.5 + 2y * -0.5) = 0
5 + 1y + (-5 + -1y) = 0

Reorder the terms:
5 + -5 + 1y + -1y = 0

Combine like terms: 5 + -5 = 0
0 + 1y + -1y = 0
1y + -1y = 0

Combine like terms: 1y + -1y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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