0.2(d-6)=0.3d/5-3+0.1d

Solution for 0.2(d-6)=0.3d/5-3+0.1d equation:

0.2(d-6)=0.3d/5-3+0.1d

We move all terms to the left:

0.2(d-6)-(0.3d/5-3+0.1d)=0


Domain of the equation: 5-3+0.1d)!=0

We move all terms containing d to the left, all other terms to the right

0.1d)!=-2

d!=-2/1

d!=-2

d∈R


We add all the numbers together, and all the variables

0.2(d-6)-(0.1d+0.3d/5-3)=0

We multiply parentheses

0.2d-(0.1d+0.3d/5-3)-1.2=0

We get rid of parentheses

0.2d-0.1d-0.3d/5+3-1.2=0

We multiply all the terms by the denominator


(0.2d)*5-(0.1d)*5-0.3d+3*5-(1.2)*5=0

We add all the numbers together, and all the variables

(+0.2d)*5-(+0.1d)*5-0.3d+3*5-(1.2)*5=0

We add all the numbers together, and all the variables

-0.3d+(+0.2d)*5-(+0.1d)*5+9=0

We multiply parentheses

-0.3d+0d-0d+9=0

We add all the numbers together, and all the variables

-0.3d+9=0

We move all terms containing d to the left, all other terms to the right

-0.3d=-9

d=-9/-0.3

d=+30