0.2(c-4)1=0.15(c+2)

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Solution for 0.2(c-4)1=0.15(c+2) equation: 


Simplifying
0.2(c + -4) * 1 = 0.15(c + 2)

Reorder the terms:
0.2(-4 + c) * 1 = 0.15(c + 2)

Reorder the terms for easier multiplication:
0.2 * 1(-4 + c) = 0.15(c + 2)

Multiply 0.2 * 1
0.2(-4 + c) = 0.15(c + 2)
(-4 * 0.2 + c * 0.2) = 0.15(c + 2)
(-0.8 + 0.2c) = 0.15(c + 2)

Reorder the terms:
-0.8 + 0.2c = 0.15(2 + c)
-0.8 + 0.2c = (2 * 0.15 + c * 0.15)
-0.8 + 0.2c = (0.3 + 0.15c)

Solving
-0.8 + 0.2c = 0.3 + 0.15c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-0.15c' to each side of the equation.
-0.8 + 0.2c + -0.15c = 0.3 + 0.15c + -0.15c

Combine like terms: 0.2c + -0.15c = 0.05c
-0.8 + 0.05c = 0.3 + 0.15c + -0.15c

Combine like terms: 0.15c + -0.15c = 0.00
-0.8 + 0.05c = 0.3 + 0.00
-0.8 + 0.05c = 0.3

Add '0.8' to each side of the equation.
-0.8 + 0.8 + 0.05c = 0.3 + 0.8

Combine like terms: -0.8 + 0.8 = 0.0
0.0 + 0.05c = 0.3 + 0.8
0.05c = 0.3 + 0.8

Combine like terms: 0.3 + 0.8 = 1.1
0.05c = 1.1

Divide each side by '0.05'.
c = 22

Simplifying
c = 22

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