0.2(4x2+12)=4

Solution for 0.2(4x2+12)=4 equation:

0.2(4x^2+12)=4

We move all terms to the left:

0.2(4x^2+12)-(4)=0

We multiply parentheses

0.8x^2+2.4-4=0

We add all the numbers together, and all the variables

0.8x^2-1.6=0

a = 0.8; b = 0; c = -1.6;
Δ = b2-4ac
Δ = 02-4·0.8·(-1.6)
Δ = 5.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.12}}{2*0.8}=\frac{0-\sqrt{5.12}}{1.6}
=-\frac{\sqrt{}}{1.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.12}}{2*0.8}=\frac{0+\sqrt{5.12}}{1.6}
=\frac{\sqrt{}}{1.6}
$