0.2(2x-6)+x/2=0.3x+0.9

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Solution for 0.2(2x-6)+x/2=0.3x+0.9 equation: 



0.2(2x-6)+x/2=0.3x+0.9

We move all terms to the left:

0.2(2x-6)+x/2-(0.3x+0.9)=0

We multiply parentheses

0.4x+x/2-(0.3x+0.9)-1.2=0

We get rid of parentheses

0.4x+x/2-0.3x-0.9-1.2=0

We multiply all the terms by the denominator


(0.4x)*2+x-(0.3x)*2-(0.9)*2-(1.2)*2=0

We add all the numbers together, and all the variables

(+0.4x)*2+x-(+0.3x)*2-(0.9)*2-(1.2)*2=0

We add all the numbers together, and all the variables

x+(+0.4x)*2-(+0.3x)*2-4.2=0

We multiply parentheses

x+0x-0x-4.2=0

We add all the numbers together, and all the variables

x-4.2=0

We move all terms containing x to the left, all other terms to the right

x=4.2

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