0.2(10b+60)=4(b-12)

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Solution for 0.2(10b+60)=4(b-12) equation: 



0.2(10b+60)=4(b-12)

We move all terms to the left:

0.2(10b+60)-(4(b-12))=0

We multiply parentheses

2b-(4(b-12))+12=0



We calculate terms in parentheses: -(4(b-12)), so:

4(b-12)

We multiply parentheses

4b-48

Back to the equation:

-(4b-48)



We get rid of parentheses

2b-4b+48+12=0

We add all the numbers together, and all the variables

-2b+60=0

We move all terms containing b to the left, all other terms to the right

-2b=-60

b=-60/-2

b=+30

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