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0.1x^2+0.5x+15=22
We move all terms to the left:
0.1x^2+0.5x+15-(22)=0
We add all the numbers together, and all the variables
0.1x^2+0.5x-7=0
a = 0.1; b = 0.5; c = -7;
Δ = b2-4ac
Δ = 0.52-4·0.1·(-7)
Δ = 3.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{3.05}}{2*0.1}=\frac{-0.5-\sqrt{3.05}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{3.05}}{2*0.1}=\frac{-0.5+\sqrt{3.05}}{0.2} $
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