0.16x+0.9(x-3)=0.01(2x-2)

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Solution for 0.16x+0.9(x-3)=0.01(2x-2) equation:



0.16x+0.9(x-3)=0.01(2x-2)
We move all terms to the left:
0.16x+0.9(x-3)-(0.01(2x-2))=0
We multiply parentheses
0.16x+0.9x-(0.01(2x-2))-2.7=0
We calculate terms in parentheses: -(0.01(2x-2)), so:
0.01(2x-2)
We multiply parentheses
0.02x-0.02
Back to the equation:
-(0.02x-0.02)
We add all the numbers together, and all the variables
1.06x-(0.02x-0.02)-2.7=0
We get rid of parentheses
1.06x-0.02x+0.02-2.7=0
We add all the numbers together, and all the variables
1.04x-2.68=0
We move all terms containing x to the left, all other terms to the right
1.04x=2.68
x=2.68/1.04
x=2+0.6/1.04

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