0.16(y-7)+0.20y=0.12y-1

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Solution for 0.16(y-7)+0.20y=0.12y-1 equation: 



0.16(y-7)+0.20y=0.12y-1

We move all terms to the left:

0.16(y-7)+0.20y-(0.12y-1)=0

We add all the numbers together, and all the variables

0.20y+0.16(y-7)-(0.12y-1)=0

We multiply parentheses

0.20y+0.16y-(0.12y-1)-1.12=0

We get rid of parentheses

0.20y+0.16y-0.12y+1-1.12=0

We add all the numbers together, and all the variables

0.24y-0.12=0

We move all terms containing y to the left, all other terms to the right

0.24y=0.12

y=0.12/0.24

y=0.12/0.24

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