0.16(y-7)+0.20y=0.04y-0.03(40)

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Solution for 0.16(y-7)+0.20y=0.04y-0.03(40) equation: 



0.16(y-7)+0.20y=0.04y-0.03(40)

We move all terms to the left:

0.16(y-7)+0.20y-(0.04y-0.03(40))=0

We add all the numbers together, and all the variables

0.16(y-7)+0.20y-(0.04y-0.034)=0

We add all the numbers together, and all the variables

0.20y+0.16(y-7)-(0.04y-0.034)=0

We multiply parentheses

0.20y+0.16y-(0.04y-0.034)-1.12=0

We get rid of parentheses

0.20y+0.16y-0.04y+0.034-1.12=0

We add all the numbers together, and all the variables

0.32y-1.086=0

We move all terms containing y to the left, all other terms to the right

0.32y=1.086

y=1.086/0.32

y=3+0.126/0.32

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