0.15x+0.8(x-4)=0.01(3x-2)

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Solution for 0.15x+0.8(x-4)=0.01(3x-2) equation: 



0.15x+0.8(x-4)=0.01(3x-2)

We move all terms to the left:

0.15x+0.8(x-4)-(0.01(3x-2))=0

We multiply parentheses

0.15x+0.8x-(0.01(3x-2))-3.2=0



We calculate terms in parentheses: -(0.01(3x-2)), so:

0.01(3x-2)

We multiply parentheses

0.03x-0.02

Back to the equation:

-(0.03x-0.02)



We add all the numbers together, and all the variables

0.95x-(0.03x-0.02)-3.2=0

We get rid of parentheses

0.95x-0.03x+0.02-3.2=0

We add all the numbers together, and all the variables

0.92x-3.18=0

We move all terms containing x to the left, all other terms to the right

0.92x=3.18

x=3.18/0.92

x=3+0.42/0.92

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