0.14x+0.3(x-3)=0.01(2x-2)

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Solution for 0.14x+0.3(x-3)=0.01(2x-2) equation: 



0.14x+0.3(x-3)=0.01(2x-2)

We move all terms to the left:

0.14x+0.3(x-3)-(0.01(2x-2))=0

We multiply parentheses

0.14x+0.3x-(0.01(2x-2))-0.9=0



We calculate terms in parentheses: -(0.01(2x-2)), so:

0.01(2x-2)

We multiply parentheses

0.02x-0.02

Back to the equation:

-(0.02x-0.02)



We add all the numbers together, and all the variables

0.44x-(0.02x-0.02)-0.9=0

We get rid of parentheses

0.44x-0.02x+0.02-0.9=0

We add all the numbers together, and all the variables

0.42x-0.88=0

We move all terms containing x to the left, all other terms to the right

0.42x=0.88

x=0.88/0.42

x=2+0.04/0.42

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