0.13x+0.5(x-4)=0.01(4x-1)

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Solution for 0.13x+0.5(x-4)=0.01(4x-1) equation: 



0.13x+0.5(x-4)=0.01(4x-1)

We move all terms to the left:

0.13x+0.5(x-4)-(0.01(4x-1))=0

We multiply parentheses

0.13x+0.5x-(0.01(4x-1))-2=0



We calculate terms in parentheses: -(0.01(4x-1)), so:

0.01(4x-1)

We multiply parentheses

0.04x-0.01

Back to the equation:

-(0.04x-0.01)



We add all the numbers together, and all the variables

0.63x-(0.04x-0.01)-2=0

We get rid of parentheses

0.63x-0.04x+0.01-2=0

We add all the numbers together, and all the variables

0.59x-1.99=0

We move all terms containing x to the left, all other terms to the right

0.59x=1.99

x=1.99/0.59

x=3+0.22/0.59

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