0.12x+0.9(x-2)=0.01(4x-5)

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Solution for 0.12x+0.9(x-2)=0.01(4x-5) equation: 



0.12x+0.9(x-2)=0.01(4x-5)

We move all terms to the left:

0.12x+0.9(x-2)-(0.01(4x-5))=0

We multiply parentheses

0.12x+0.9x-(0.01(4x-5))-1.8=0



We calculate terms in parentheses: -(0.01(4x-5)), so:

0.01(4x-5)

We multiply parentheses

0.04x-0.05

Back to the equation:

-(0.04x-0.05)



We add all the numbers together, and all the variables

1.02x-(0.04x-0.05)-1.8=0

We get rid of parentheses

1.02x-0.04x+0.05-1.8=0

We add all the numbers together, and all the variables

0.98x-1.75=0

We move all terms containing x to the left, all other terms to the right

0.98x=1.75

x=1.75/0.98

x=1+0.77/0.98

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