0.12x+0.6(24-x)=12

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Solution for 0.12x+0.6(24-x)=12 equation: 



0.12x+0.6(24-x)=12

We move all terms to the left:

0.12x+0.6(24-x)-(12)=0

We add all the numbers together, and all the variables

0.12x+0.6(-1x+24)-12=0

We multiply parentheses

0.12x-0.6x+14.4-12=0

We add all the numbers together, and all the variables

-0.48x+2.4=0

We move all terms containing x to the left, all other terms to the right

-0.48x=-2.4

x=-2.4/-0.48

x=+5

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