0.12=9+(100-x)/x

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Solution for 0.12=9+(100-x)/x equation: 



0.12=9+(100-x)/x

We move all terms to the left:

0.12-(9+(100-x)/x)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(9+(-1x+100)/x)+0.12=0

We multiply all the terms by the denominator


-(9+(-1x+100)+(0.12)*x)=0



We calculate terms in parentheses: -(9+(-1x+100)+(0.12)*x), so:

9+(-1x+100)+(0.12)*x

determiningTheFunctionDomain
(-1x+100)+(0.12)*x+9

We multiply parentheses

(-1x+100)+0.12x+9

We get rid of parentheses

-1x+0.12x+100+9

We add all the numbers together, and all the variables

-0.88x+109

Back to the equation:

-(-0.88x+109)



We get rid of parentheses

0.88x-109=0

We move all terms containing x to the left, all other terms to the right

0.88x=109

x=109/0.88

x=123+0.76000000000001/0.88

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