0.12(y-7)+0.20y=0.14-0.03(10)

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Solution for 0.12(y-7)+0.20y=0.14-0.03(10) equation: 



0.12(y-7)+0.20y=0.14-0.03(10)

We move all terms to the left:

0.12(y-7)+0.20y-(0.14-0.03(10))=0

We add all the numbers together, and all the variables

0.12(y-7)+0.20y-(0.109)=0

We add all the numbers together, and all the variables

0.20y+0.12(y-7)-0.109=0

We multiply parentheses

0.20y+0.12y-0.84-0.109=0

We add all the numbers together, and all the variables

0.32y-0.949=0

We move all terms containing y to the left, all other terms to the right

0.32y=0.949

y=0.949/0.32

y=2+0.309/0.32

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